(5x+2)(2x^2-13x-7)=0

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Solution for (5x+2)(2x^2-13x-7)=0 equation:


Simplifying
(5x + 2)(2x2 + -13x + -7) = 0

Reorder the terms:
(2 + 5x)(2x2 + -13x + -7) = 0

Reorder the terms:
(2 + 5x)(-7 + -13x + 2x2) = 0

Multiply (2 + 5x) * (-7 + -13x + 2x2)
(2(-7 + -13x + 2x2) + 5x * (-7 + -13x + 2x2)) = 0
((-7 * 2 + -13x * 2 + 2x2 * 2) + 5x * (-7 + -13x + 2x2)) = 0
((-14 + -26x + 4x2) + 5x * (-7 + -13x + 2x2)) = 0
(-14 + -26x + 4x2 + (-7 * 5x + -13x * 5x + 2x2 * 5x)) = 0
(-14 + -26x + 4x2 + (-35x + -65x2 + 10x3)) = 0

Reorder the terms:
(-14 + -26x + -35x + 4x2 + -65x2 + 10x3) = 0

Combine like terms: -26x + -35x = -61x
(-14 + -61x + 4x2 + -65x2 + 10x3) = 0

Combine like terms: 4x2 + -65x2 = -61x2
(-14 + -61x + -61x2 + 10x3) = 0

Solving
-14 + -61x + -61x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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